How to solve balanced parentheses problem with regex in ruby
This is one of the classic interview questions that is classically solved with a stack algorithm. Despite regular expressions are not the most efficient way in terms of computation, I’m going to show a solution using subexpression call syntax only to show a different approach.
Your objective is to create an algorithm to validate whether the parentheses in a given string are balanced on not. For example:
Just in case you don’t remember the syntax. These are the instructions considering that there are reserved characters like: “(“, “)”, “.”, that you are going to have to use to escape it using “\” at the beginning. For example, if you want to use a parenthesis you should use: \(
On the other hand, we will use the method match? for simplicity, because it returns true/false depending on the input that we are using with our regular expression.
So, when we try to solve something using regular expressions our knowledge is mainly limited to the classic syntax that we are able to test online. Let's begin with the easiest idea. We want to validate if we have something like: “()”, “()()”, etc.
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